## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 11 - Section 11.2 - Solving Quadratic Equations by Completing the Square - Exercise Set: 69

#### Answer

$x=15$

#### Work Step by Step

$\dfrac{1}{x}+\dfrac{2}{5}=\dfrac{7}{x} \\ \dfrac{5+2x}{5x}=\dfrac{7}{x} \\ x(5+2x)=7(5x) \\ 5x+2x^2=35x \\ 2x^2+5x-35x=0 \\ 2x^2 -30x=0 \\ x^2-15x=0 \\ x(x-15)=0 \\$ But the solution is only $x=15$, because if $x=0$ then the original ecuation would be undefined

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