Answer
$x = (5+\sqrt 23, 5-\sqrt 23)$
Work Step by Step
Step-1 : Subtract $2$ on both sides of the equation
$x^2-10x=-2$
Step -2 : Add the square of half of the co-efficient of $x$ to both sides.
Co-efficient of $x =-10$
Half of $-10 = \frac{1}{2}×-10=-5$
Square of $-5$ is $-5×-5=25$
The equation becomes $x^2-10x+25=-2+25$
Step-3 Factor the trinomial and simplify the right hand side.
$(x-5)^2=23$
Step-4 Use the square root property and solve for $x$
$(x-5)=±\sqrt 23 $
Step-5 Add 5 on both the sides
$x=5±\sqrt 23$
Therefore the solution set is $(5+\sqrt 23, 5-\sqrt 23)$
