## Algebra: A Combined Approach (4th Edition)

{$-4-\sqrt15$}, {$-4+\sqrt15$} This above answer is written as a solution set, however it can also be written as: $x=-4\pm\sqrt15$
Solve by completing the square. $x^2+8x+1$ Take the c term to the other side. $-1=x^2+8x$ Create a perfect square trinomial, and add the new c term to the other side as well. $-1+16=x^2+8x+16$ Factor. $15=(x+4)^2$ Solve. $\sqrt(x+4)^2=\sqrt15$ $x=-4\pm\sqrt15$