Answer
$x=(1-\sqrt 3, 1+\sqrt 3)$
Work Step by Step
Step-1 : Add $2$ from both sides of the equation
$x^2-2x=2$
Step -2 : Add the square of half of the co-efficient of $x$ to both sides.
Co-efficient of $x =-2$
Half of $-2 = \frac{1}{2}×-2=-1$
Square of $-1$ is $-1×-1=1$
The equation becomes $x^2-2x+1=2+1$
Step-3 Factor the trinomial and simplify the right hand side.
$(x-1)^2=3$
Step-4 Use the square root property and solve for $x$
$(x-1)=±\sqrt 3$
Step-5 Add 1 on both the sides
$x=1±\sqrt 3$
Therefore the solution set is $(1-\sqrt 3, 1+\sqrt 3)$
