Answer
$x=1$
Work Step by Step
$\sqrt {3x+1} -2=0$
$\sqrt {3x+1} -2+2=0+2$
$\sqrt{3x+1}=2$
$(\sqrt{3x+1})^2=2^2$
$3x+1=4$
$3x=3$
$3x/3=3/3$
$x=1$
$\sqrt {3x+1} -2=0$
$\sqrt {3*1+1} -2=0$
$\sqrt {3+1} -2=0$
$\sqrt {4} -2=0$
$2-2=0$
$0=0$ (true)