Answer
$x=47$
Work Step by Step
$\sqrt {3x+3}-4=8$
$\sqrt {3x+3}=12$
$(\sqrt {3x+3})^2=12^2$
$3x+3=144$
$3x=141$
$3x/3=141/3$
$x=47$
$\sqrt {3x+3}-4=8$
$\sqrt {3*47+3}-4=8$
$\sqrt {141+3}-4=8$
$\sqrt {144}-4=8$
$12-4=8$ (true)
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Exercise Set - Page 728: 10
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