Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.6 - Radical Equations and Problem Solving - Exercise Set - Page 728: 17

Answer

$x=-4$

Work Step by Step

$x-\sqrt {4-3x}=-8$ $x-\sqrt {4-3x}+8+\sqrt {4-3x}=-8+8+\sqrt {4-3x}$ $x+8 = \sqrt {4-3x}$ $(x+8)^2 =(\sqrt {4-3x})^2$ $x^2+16x+64=4-3x$ $x^2+19x+60=0$ $(x+15)(x+4)=0$ $x+15=0$ $x=-15$ $x+4=0$ $x=-4$ $x-\sqrt {4-3x}=-8$ $-15-\sqrt {4-3*-15}=-8$ $-15-\sqrt {4--45}=-8$ $-15-\sqrt {49}=-8$ $-15-7=-8$ $-22\ne-8$ (false) $x-\sqrt {4-3x}=-8$ $-4-\sqrt {4-3*-4}=-8$ $-4-\sqrt {4+12}=-8$ $-4-\sqrt {16}=-8$ $-4-4=-8$ $-8=-8$ (true)
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