Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 719: 83

Answer

a) $y\sqrt {15xy}/6x^2$ b) $y\sqrt {15xy}/6x^2$ c) There are multiple expressions by which the numerator and denominator can be rationalized and which result in the same result.

Work Step by Step

$\sqrt {5y^3}\sqrt {12x^3}/(\sqrt {12x^3}\sqrt {12x^3})$ a) $\sqrt {5y^3}/\sqrt {12x^3}$ $(\sqrt {5y^3})(\sqrt {12x^3})/(\sqrt {12x^3})(\sqrt {12x^3})$ $(\sqrt {5y^3})(\sqrt {12x^3})/(\sqrt {12x^3})(\sqrt {12x^3})$ $(\sqrt {5y^3})(\sqrt {12x^3})/12x^3$ $(\sqrt {5*12*x^3*y^3})/12x^3$ $(\sqrt {5*3*4*x^2*x*y^2*y})/12x^3$ $2xy(\sqrt {5*3*x*y})/12x^3$ $y/6x^2(\sqrt {5*3*x*y})$ $y/6x^2(\sqrt {15xy})$ b) $(\sqrt {5y^3})/(\sqrt {12x^3})$ $(\sqrt {5y^3})(\sqrt {3x})/(\sqrt {12x^3})(\sqrt {3x})$ $(\sqrt {15xy^3})/(\sqrt {36x^4})$ $(\sqrt {15xy^2*y})/(\sqrt {(6x^2)^2})$ $\frac{y}{6x^2}*\sqrt {15xy}$
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