#### Answer

{$2,6$}

#### Work Step by Step

$x^{2}-8x=-12$
$x^{2}-8x+12=0$
$x^{2}-2x-6x+12=0$
$x(x-2)-6(x-2)=0$
$(x-2)(x-6)=0$
$x-2=0$ and $x-6=0$
$x=2$ and $x=6$
The solution set is {$2,6$}.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

{$2,6$}

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