## Algebra: A Combined Approach (4th Edition)

{$2,6$}
$x^{2}-8x=-12$ $x^{2}-8x+12=0$ $x^{2}-2x-6x+12=0$ $x(x-2)-6(x-2)=0$ $(x-2)(x-6)=0$ $x-2=0$ and $x-6=0$ $x=2$ and $x=6$ The solution set is {$2,6$}.