Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 719: 77

Answer

{$2,6$}

Work Step by Step

$x^{2}-8x=-12$ $x^{2}-8x+12=0$ $x^{2}-2x-6x+12=0$ $x(x-2)-6(x-2)=0$ $(x-2)(x-6)=0$ $x-2=0$ and $x-6=0$ $x=2$ and $x=6$ The solution set is {$2,6$}.
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