Answer
{$2,6$}
Work Step by Step
$x^{2}-8x=-12$
$x^{2}-8x+12=0$
$x^{2}-2x-6x+12=0$
$x(x-2)-6(x-2)=0$
$(x-2)(x-6)=0$
$x-2=0$ and $x-6=0$
$x=2$ and $x=6$
The solution set is {$2,6$}.
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