Answer
{$-\frac{1}{2}, 6$}
Work Step by Step
$(x-6)(2x+1)=0$
$(x-6)=0$ and $(2x+1)=0$
$(x-6)=0$ and $2x=-1$
$x=6$ and $x=-\frac{1}{2}$
Therefore, the solution set is {$-\frac{1}{2}, 6$}.
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 719: 75
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