Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 10 - Section 10.5 - Rationalizing Numerators and Denominators of Radical Expressions - Exercise Set - Page 719: 75


{$-\frac{1}{2}, 6$}

Work Step by Step

$(x-6)(2x+1)=0$ $(x-6)=0$ and $(2x+1)=0$ $(x-6)=0$ and $2x=-1$ $x=6$ and $x=-\frac{1}{2}$ Therefore, the solution set is {$-\frac{1}{2}, 6$}.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.