#### Answer

$-\frac{4a}{b^3}$

#### Work Step by Step

$-\sqrt[3] \frac{64a^{3}}{b^9}=-\frac{4a}{b^3}$
Take the cube root of the numerator and the denominator.

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-\frac{4a}{b^3}$

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