#### Answer

$x^2y^3$

#### Work Step by Step

$\sqrt[4] {x^{8}y^{12}}=x^2y^3$
because,
$(x^2y^3)^4=x^{8}y^{12}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$x^2y^3$

$\sqrt[4] {x^{8}y^{12}}=x^2y^3$
because,
$(x^2y^3)^4=x^{8}y^{12}$

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