#### Answer

$-2x^2y$

#### Work Step by Step

$\sqrt[5] {-32x^{10}y^5}=-2x^2y$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$-2x^2y$

$\sqrt[5] {-32x^{10}y^5}=-2x^2y$

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