## Algebra 2 Common Core

$$\frac{4c}{5}$$
Factor the numerator and the denominator and cancel common terms: $$\frac{28c^{2}(d-3)}{35c(d-3)}=\frac{4\times 7\times c\times c\times(d-3)}{5\times 7\times c\times (d-3)}=\frac{4c}{5}.$$