Answer
$$\frac{13}{6x}$$
Work Step by Step
A common denominator of $2x$ and $3x$ is $6x$, so
$$\frac{13}{2x}-\frac{13}{3x}=\bigg(\frac{13}{2x}\bigg)\bigg(\frac{3}{3}\bigg)-\bigg(\frac{13}{3x}\bigg)\bigg(\frac{2}{2}\bigg)=\frac{39}{6x}-\frac{26}{6x}=\frac{13}{6x}.$$