## Algebra 2 Common Core

$$\frac{4x^{2}}{5}$$
First, find and divide out any common factors: $$\frac{7x}{8}\times \frac{32x}{35}=\bigg(\frac{7\times x}{8}\bigg)\times \bigg(\frac{8\times 4\times x}{7\times 5}\bigg).$$ In this case, cancel the factors $7$ and $8$, and the result is $$\bigg(\frac{x}{1}\bigg)\times \bigg(\frac{4\times x}{5}\bigg)=\frac{4x^{2}}{5}.$$