Answer
$y-11=\frac{8}{3}\left(x-3\right)$
Work Step by Step
RECALL:
(1) The point-slope form of a line's equation is $y-y_1=m(x-x_1)$ where $m$ is the slope and the line contains the point $(x_1, y_1)$.
(2) The slope of a line through the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula:
$$m=\dfrac{y_2-y_1}{x_2-x_1}$$
Solve for the slope of the line through the given points using the formula in (2) above to obtain:
\begin{align*}
m&=\dfrac{11-3}{3-0}\\\\
m&=\dfrac{8}{3}
\end{align*}
Thus, using the point $(3, 11)$, the point-slope form of the line through the given two points is:
\begin{align*}
y-y_1&=m(x-x_1)\\
y-11&=\frac{8}{3}\left(x-3\right)
\end{align*}
