Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-2 Arithmetic Sequences - Practice and Problem-Solving Exercises - Page 577: 72

Answer

$d=2.2, a_1=-9$

Work Step by Step

With $a_4=-2.4$, the value of $a_6$ can be found by adding the common difference $d$ twice. Since $a_4=-2.4$ and $a_6=2$, then: \begin{align*} a_4+2d&=a_6\\ -2.4+2d&=2\\ 2d&=2+2.4\\ 2d&=4.4\\ d&=\frac{4.4}{2}\\ d&=2.2 \end{align*} To find $a_1$, use the formula $a_n=a_1+d(n-1)$ to obtain: \begin{align*} a_6&=a_1+2.2(6-1)\\ 2&=a_1+2.2(5)\\ 2&=a_1+11\\ 2-11&=a_1\\ -9&=a_1 \end{align*}
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