Answer
$a_{11}=21k-43$
Work Step by Step
To find $a_{11}$, use the formula $a_n=a_1+d(n-1)$ to obtain:
\begin{align*}
a_{n}&=a_1+d(n-1)\\
a_{11}&=(k+7)+(2k-5)(11-1)\\
a_{11}&=k+7+(2k-5)(10)\\
a_{11}&=k+7+20k-50\\
a_{11}&=21k-43
\end{align*}
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 9 - Sequences and Series - 9-2 Arithmetic Sequences - Practice and Problem-Solving Exercises - Page 577: 74
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