Answer
$225$
Work Step by Step
The $n^{th}$ term $a_{n}$ of an arithmetic sequence is given by the formula:
$a_{n} =a_{1} + (n-1) d$
Where:
$d$ = common difference
$a_{1}$ = first term
$n$ = term number
The common difference $d$ of the arithmetic sequence is:
$d=113-109=4$
The given arithmetic sequence has
$d=4$
$a_{1}=101$
$n=32$
Use the given values and the formula above to find the $32^{\text{nd}}$ term:
$a_{32}= 101+(32-1) 4$
$a_{32} = 101+ 4(31)$
$a_{32}=225$
