Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 9 - Sequences and Series - 9-2 Arithmetic Sequences - Practice and Problem-Solving Exercises - Page 575: 30

Answer

$\dfrac{7}{10}$

Work Step by Step

The $16^{\text{th}}$ term is $\dfrac{1}{5}$ and the common difference is $\dfrac{1}{2}$ so we simply add $\dfrac{1}{2}$ to $\frac{1}{5}$ to get the $17^{\text{th}}$ term: $a_{17}=a_{16}+ d$ $a_{17}=\dfrac{1}{5} +\dfrac{1}{2}$ $a_{17}=\dfrac{2}{10} +\dfrac{5}{10}$ $a_{17}=\dfrac{7}{10}$
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