Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Review - Page 489: 30

Answer

$-5$

Work Step by Step

The given expression is equivalent to: \begin{align*} &=\log_{10}{\left(\frac{1}{10^5}\right)}\\\\ &=\log_{10}{\left(10^{-5}\right)} \end{align*} RECALL: $$\log_a{\left(a^n\right)}=n$$ Use the rule above to obtain: \begin{align*} \log_{10}{\left(10^{-5}\right)}&=-5 \end{align*}
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