Chapter 7 - Exponential and Logarithmic Functions - Chapter Review - Page 489: 29

$-2$

The given expression is equivalent to: \begin{align*} &=\log_3{\left(\frac{1}{3^2}\right)}\\\\ &=\log_2{\left(3^{-2}\right)} \end{align*} RECALL: $$\log_a{\left(a^n\right)}=n$$ Use the rule above to obtain: \begin{align*} \log_3{\left(3^{-2}\right)}&=-2 \end{align*}