Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - 7-6 Natural Logarithms - Practice and Problem-Solving Exercises - Page 483: 71

Answer

$3$

Work Step by Step

Note that: $\sqrt{36}=\sqrt{6^2}=6$ $\sqrt4 = \sqrt{2^2} = 2$ Thus, $\dfrac{\sqrt{36}}{\sqrt4}=\dfrac{6}{2}=3$
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