Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 423: 13

Answer

$$\frac{x^2}{2}$$

Work Step by Step

RECALL: (1) If $n$ is odd, then $\sqrt[n]{a^n}=a$. (2) If $n$ is even, then $\sqrt[n]{a^n} = |a|$ Use rule (1) above to obtain: \begin{align*} \sqrt{\frac{9x^4}{36}}&=\sqrt{\frac{9}{36} \cdot x^4}\\\\ &=\sqrt{\left(\frac{3}{6}\right)(x^2)^2}\\\\ &=\frac{3}{6}\cdot |x^2|\\\\ &=\frac{1}{2}\cdot |x^2| \end{align*} However, since $|x^2|$ will never be negative, then $|x^2|=x^2$. Thus, the solution is: $$=\frac{1}{2}x^2\\\\ =\frac{x^2}{2}$$
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