Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 423: 8

Answer

$$-2$$

Work Step by Step

Recall: For any real number $a$, $\sqrt[3]{a^3}=a$. Using the rule above gives: \begin{align*} -\sqrt[3]{8}&=-\sqrt[3]{(2)(2)(2)}\\ &=-\sqrt[3]{(2)^3}\\ &=-2 \end{align*}
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