Answer
$$-2$$
Work Step by Step
Recall:
For any real number $a$, $\sqrt[3]{a^3}=a$.
Using the rule above gives:
\begin{align*}
\sqrt[3]{-8}&=\sqrt[3]{(-2)(-2)(-2)}\\
&=\sqrt[3]{(-2)^3}\\
&=-2
\end{align*}
Algebra 2 Common Core
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133186024
ISBN 13:
978-0-13318-602-4
Chapter 6 - Radical Functions and Rational Exponents - Chapter Review - Page 423: 7
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