Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Practice and Problem-Solving Exercises - Page 395: 15

Answer

$x = 4$

Work Step by Step

$\sqrt{3x+4} = 4$ Square both sides to remove the square root. $3x+4 = 16$ Subtract $4$ from both sides. $3x = 12$ Divide both sides by $3$. $x = 4$ Check the answer for extraneous solutions. Does the answer make the original statement true? $\sqrt{3(4)+4} = 4$ $\sqrt{12+4} = 4$ $\sqrt{16} = 4$ $4= 4$ Since the original statement is true, we can conclude that $x = 4$.
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