Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Practice and Problem-Solving Exercises - Page 395: 14

$2$

$\sqrt {x+2} -2=0$ Add 2 to both sides $\sqrt {x+2} =2$ Square both sides $\left(\sqrt {x+2}\right)^{2} =2^{2}$ $x+2 = 4$ Subtract 2 from both sides $x=2$ Substitute into original problem: $\sqrt {(2)+2} -2=0$ $\sqrt {4} -2=0$ $2-2=0$ $0=0$