Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Practice and Problem-Solving Exercises - Page 395: 11

Answer

$22$

Work Step by Step

Square both sides of the equation then simplify : $\sqrt{x+3}=5\\ \left(\sqrt{x+3}\right)^{2} = 5^{2}\\ x+3 = 25\\$ Subtract $3$ from each side: $x+3-3=25-3\\ x=22$
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