Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Lesson Check - Page 394: 5

$1$

Subtract $5$ from both sides: $5-2\sqrt{x}-5=3-5$ $-2\sqrt{x}=-2$ Divide both sides by $-2$: $\dfrac{-2\sqrt{x}}{-2}=\dfrac{-2}{-2}$ $\sqrt x=1$ Square both sides: $(\sqrt x)^2=(1)^2$ $x=1$ Substitute into original problem to check for extraneous solutions: $5-2\sqrt{(1)}=3$ $5-2(1)=3$ $5-2=3$ $3=3$