Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Lesson Check - Page 394: 1

Answer

$12$

Work Step by Step

$\sqrt{4x-23}-3=2$ Add $3$ to both sides: $\sqrt{4x-23}-3+3=2+3$ $\sqrt{4x-23}=5$ Square both sides: $(\sqrt{4x-23})^2=(5)^2$ $4x-23=25$ Add $23$ to both sides: $4x-23+23=25+23$ $4x=48$ Divide both sides by $4$: $$\frac{4x}{4}=\frac{48}{4}$$ $x=12$ Substitute into original problem to check for extraneous solutions: $\sqrt{4(12)-23}-3=2$ $\sqrt{48-23}-3=2$ $\sqrt{25}-3=2$ $5-3=2$ $2=2$
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