Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-5 Solving Square Root and Other Radical Equations - Lesson Check - Page 394: 4

Answer

$4$

Work Step by Step

Divide both sides by $3$: $\dfrac{3\sqrt{x}}{3}=\dfrac63$ $\sqrt{x}=2$ Square both sides: $(\sqrt{x})^2=2^2$ $x=4$ Substitute into original problem to check for extraneous solutions: $3\sqrt{4}=6$ $3\cdot2=6$ $6=6$
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