Chapter 6 - Radical Functions and Rational Exponents - 6-2 Multiplying and Dividing Radical Expressions - Practice and Problem-Solving Exercises - Page 373: 90

$6a^2-5a+4$

Equating the given divisor, $ a+1 ,$ to zero and then solving for the variable results to \begin{align*} a+1&=0 \\ a&=-1 .\end{align*} Using $ -1 $ in the synthetic division below, then $ (6a^3+a^2-a+4)\div(a+1) ,$ is equal to \begin{align*} 6a^2-5a+4 .\end{align*}