Answer
$2y^{5}$
Work Step by Step
Extracting the factors that are perfect powers of the index, the given expression, $
\sqrt[5]{32y^{25}}
,$ is equivalent to
\begin{align*}\require{cancel}
&
\sqrt[5]{(2y^{5})^5}
\\\\&=
2y^{5}
.\end{align*}
Hence, the given expression simplifies to $
2y^{5}
$.
