Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-2 Polynomials, Linear Factors, and Zeros - Practice and Problem-Solving Exercises - Page 295: 69


The solutions are $-\frac{5}{2}$ and $\frac{5}{2}$.

Work Step by Step

Write each term of the binomial in square form to get $(2x)^2-5^2=0$. Factor the difference of two squares to get $(2x-5)(2x+5)=0.$ Equate each factor to 0, then solve each equation for x: $2x-5=0 \text{ or } 2x+5=0 \\x=\frac{5}{2} \text{ or } x=-\frac{5}{2}.$ Thus, the solutions are $-\frac{5}{2}$ and $\frac{5}{2}$.
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