## Algebra 2 Common Core

The solution set is $\left\{\frac{1}{2}, 3\right\}$.
Factor the trinomial to get $\\(2x-1)(x-3)=0$. Equate each factor to 0, then solve each equation for x: $2x-1=0 \text{ or } x-3=0 \\x=\frac{1}{2} \text{ or } x=3.$ Thus, the solutions are $\frac{1}{2}$ and 3.