## Algebra 2 Common Core

The solution set is: $\left\{-3, 2\right\}$
Factor the trinomial to get $\\(x+3)(x-2)=0$. Equate each factor to 0, then solve each equation for x: $x+3=0 \text{ or } x-2=0 \\x=-3 \text{ or } x=2$. Thus, the solutions are -3 and 2.