Answer
$$108$$
Work Step by Step
Recall:
(1) $\left(\sqrt{a}\right)^2=|a|$
(2) $(ab)^m=a^mb^m$
Using rule (2) above gives:
\begin{align*}
\left(2\sqrt{27}\right)^2&=2^2 \cdot \left(\sqrt{27}\right)^2\\
&=4\left(\sqrt{27}\right)^2
\end{align*}
Using rule (1) above gives:
\begin{align*}
4\left(\sqrt{27}\right)^2&=4(|27|)\\
&=4(27)\\
&=108
\end{align*}