Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Square Roots and Radicals - Exercises - Page 225: 15

Answer

$$\dfrac{5\sqrt{14}}{7}$$

Work Step by Step

Simplify the radicand (expression inside the radical sign) by cancelling out the common factor $2$ to obtain: \begin{align*} \require{cancel} &=\sqrt{\dfrac{\cancel{200}^{100}}{\cancel{28}^{14}}}\\\\ &=\sqrt{\dfrac{100}{14}} \end{align*} RECALL: (1) For any real numbers $a \ge 0, b\ge0$, $\sqrt{ab}=\sqrt{a} \cdot \sqrt{b}$ (2) For any real numbers $a \ge 0, b\gt 0$, $\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}$ Use rule (2) above to obtain: \begin{align*} \sqrt{\dfrac{100}{14}}&=\dfrac{\sqrt{100}}{\sqrt{14}}\\\\ &=\dfrac{10}{\sqrt{14}} \end{align*} Rationalize the denominator by multiplying $\sqrt{14}$ to both the numerator and denominator to obtain: \begin{align*} \dfrac{10}{\sqrt{14}} \cdot \dfrac{\sqrt{14}}{\sqrt{14}}&=\dfrac{10\sqrt{14}}{\sqrt{196}}\\\\ &=\dfrac{10\sqrt{14}}{14} \end{align*} Simplify by cancelling the common factor $2$ to obtain: \begin{align*} \require{cancel} \dfrac{\cancel{10}^5\sqrt{14}}{\cancel{14}^7}&=\dfrac{5\sqrt{14}}{7} \end{align*}
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