Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Chapter Review - Page 272: 75

Answer

$13+20i$

Work Step by Step

Removing the grouping symbols, the given expression, $ (3+11i)+(10+9i) ,$ is equivalent to \begin{align*} & 3+11i+10+9i \\&= (3+10)+(11i+9i) &\text{ (combine like terms)} \\&= 13+(20i) \\&= 13+20i .\end{align*} Hence, the given expression simplifies to $ 13+20i $.
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