Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Chapter Review - Page 272: 72

Answer

$-50+40i$

Work Step by Step

Using $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ the given expression, $ (4+\sqrt{-25})(\sqrt{-100}) ,$ is equivalent to \begin{align*} & (4+\sqrt{-1}\cdot\sqrt{25})(\sqrt{-1}\cdot\sqrt{100}) \\&= (4+\sqrt{-1}\cdot5)(\sqrt{-1}\cdot10) \\&= (4+i\cdot5)(i\cdot10) &\text{ (use $i=\sqrt{-1}$)} \\&= (4+5i)(10i) \\&= 4(10i)+5i(10i) &\text{ (use Distributive Property)} \\&= 40i+50i^2 \\&= 40i+50(-1) &\text{ ($i^2=-1$)} \\&= 40i-50 \\&= -50+40i .\end{align*} Hence, the given expression simplifies to $ -50+40i $.
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