Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - Chapter Review - Page 271: 52

Answer

$x=\{ -2\sqrt{3},2\sqrt{3} \}$

Work Step by Step

Using the properties of equality, the given equation, $ 3x^2=36 ,$ is equivalent to \begin{align*} \dfrac{3x^2}{3}&=\dfrac{36}{3} \\\\ x^2&=12 .\end{align*} Getting the square root of both sides (Square Root Property), the equation above is equivalent to \begin{align*} x&=\pm\sqrt{12} \\ x&=\pm\sqrt{4\cdot3} \\ x&=\pm2\sqrt{3} .\end{align*} Hence, the solutions are $ x=\{ -2\sqrt{3},2\sqrt{3} \} $.
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