Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-8 Complex Numbers - Practice and Problem-Solving Exercises - Page 254: 68

Answer

$x=\dfrac{16}{3} \text{ and } y=-\dfrac{19}{8} $

Work Step by Step

Equating the real parts and equating the imaginary parts, the given equation, $ 3x+19i=16-8yi ,$ implies \begin{align*} 3x&=16 \\\\&\text{ and }\\\\ 19&=-8y .\end{align*} Solving each equation results to \begin{align*} 3x&=16 \\ \dfrac{3x}{3}&=\dfrac{16}{3} \\ x&=\dfrac{16}{3} \\\\&\text{ and }\\\\ 19&=-8y \\ \dfrac{19}{-8}&=\dfrac{-8y}{-8} \\ -\dfrac{19}{8}&=y .\end{align*} Hence, $ x=\dfrac{16}{3} \text{ and } y=-\dfrac{19}{8} $.
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