Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-8 Complex Numbers - Practice and Problem-Solving Exercises - Page 254: 54

Answer

$7-i$

Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property, the given expression, $ -5(1+2i)+3i(3-4i) ,$ is equivalent to \begin{align*} & -5(1)-5(2i)+3i(3)+3i(-4i) \\&= -5-10i+9i-12i^2 .\end{align*} Since $i^2=-1,$ the expression above is equivalent to \begin{align*} & -5-10i+9i-12(-1) \\&= -5-10i+9i+12 .\end{align*} Combining the real parts and the imaginary parts, the expression above is equivalent to \begin{align*} & (-5+12)+(-10i+9i) \\&= 7+(-i) \\&= 7-i .\end{align*} Hence, the simplified form of the given expression is $ 7-i $.
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