Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-8 Complex Numbers - Practice and Problem-Solving Exercises - Page 253: 27

Answer

$-\dfrac{2}{5}-\dfrac{3}{5}i$

Work Step by Step

Multiplying both the numerator and the denominator by the denominator of the given expression, $ \dfrac{3-2i}{5i} ,$ then \begin{align*}\require{cancel} & \dfrac{3-2i}{5i}\cdot\dfrac{5i}{5i} \\\\&= \dfrac{3(5i)-2i(5i)}{5i(5i)} \\\\&= \dfrac{15i-10i^2}{25i^2} \\\\&= \dfrac{15i-10(-1)}{25(-1)} &\text{ (use $i^2=-1$)} \\\\&= \dfrac{15i+10}{-25} \\\\&= -\dfrac{10+15i}{25} \\\\&= -\dfrac{\cancel{10}^2+\cancel{15}^3i}{\cancel{25}^5} &\text{ (divide by $5$)} \\\\&= -\dfrac{2+3i}{5} \\\\&= -\dfrac{2}{5}-\dfrac{3}{5}i .\end{align*} Hence, the simplified form of the given expression is $ -\dfrac{2}{5}-\dfrac{3}{5}i $.
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