Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-8 Complex Numbers - Practice and Problem-Solving Exercises - Page 253: 22

Answer

$-7-10i$

Work Step by Step

Removing the grouping symbols, the given expression, $ (-6-7i)-(1+3i) ,$ is equivalent to \begin{align*} -6-7i-1-3i .\end{align*} Combining the real parts and the imaginary parts, the expression above is equivalent to \begin{align*} & (-6-1)+(-7i-3i) \\&= -7+(-10i) \\&= -7-10i .\end{align*} Hence, the simplified form of the given expression is $ -7-10i $.
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