Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Practice and Problem-Solving Exercises - Page 229: 16

Answer

$x=\left\{ -\dfrac{2}{3},0 \right\}$

Work Step by Step

The factored form of the given equation, $ 6x^2+4x=0 ,$ is \begin{align*} 2x(3x+2)=0 .\end{align*} Equating each factor to zero (Zero Product Property), the solutions of the equation above are \begin{align*} 2x&=0 \\\\\text{ OR}\\\\ 3x+2&=0 .\end{align*} Solving each equation above results to \begin{align*} 2x&=0 \\ \dfrac{2x}{2}&=\dfrac{0}{2} \\ x&=0 \\\\\text{ OR}\\\\ 3x+2&=0 \\ 3x&=-2 \\ \dfrac{3x}{3}&=-\dfrac{2}{3} \\ x&=-\dfrac{2}{3} .\end{align*} Hence, the solutions are $ x=\left\{ -\dfrac{2}{3},0 \right\} .$
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