Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 4 - Quadratic Functions and Equations - 4-5 Quadratic Equations - Practice and Problem-Solving Exercises - Page 229: 13

Answer

$x=\left\{ -2,-1 \right\}$

Work Step by Step

The factored form of the given equation, $ 2x^2+6x=-4 ,$ is \begin{align*} 2x^2+6x+4&=0 \\ 2(x^2+3x+2)&=0 \\\\ \dfrac{2(x^2+3x+2)}{2}&=\dfrac{0}{2} \\\\ x^2+3x+2&=0 \\ (x+2)(x+1)&=0 .\end{align*} Equating each factor to zero (Zero Product Property), the solutions of the equation above are \begin{align*} x+2&=0 \\\\\text{ OR}\\\\ x+1&=0 .\end{align*} Solving each equation above results to \begin{align*} x+2&=0 \\ x&=-2 \\\\\text{ OR}\\\\ x+1&=0 \\ x&=-1 .\end{align*} Hence, the solutions are $ x=\left\{ -2,-1 \right\} .$
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