Answer
$(t-7)^2$
Work Step by Step
Using the factoring of trinomials in the form $x^2+bx+c,$ the given $\text{
expression
}$
\begin{align*}
t^2-14t+49
\end{align*} has $c=
49
$ and $b=
-14
.$
The two numbers with a product of $c$ and a sum of $b$ are $\left\{
-7,-7
\right\}.$ Using these two numbers, the factored form of the $\text{
expression
}$ above is
\begin{align*}
&
(t-7)(t-7)
\\&=
(t-7)^2
.\end{align*}
